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calculating dry weight from wet glaze

updated sat 19 jun 04

 

Roger Graham on fri 18 jun 04


For the mathematically challenged, here's another way to find the weight of
dry ingredients in a 1 litre volume of glaze. Let's agree to use the letters
"SG" for the density of the glaze in grams per millilitre. I'm told it's
politically incorrect to keep calling it "specific gravity", but it's the
same thing.

Now the weight of dry matter in grams, in 1 litre of glaze, will be
1625(SG-1), assuming an average value of 2.6 grams per mL for the dry
ingredients.

For example, if the SG of the glaze is 1.3, the dry matter in 1 litre will
be 1625 (1.3-1) which is 1625 x 0.3 or about 487 grams.

Another example: If the SG of the glaze is 1.4, the dry matter in 1 litre
will be 1625 x 0.4, or about 650 grams

That didn't hurt much, did it? Not witchcraft. Just Brongniart's formula
rearranged. A lot simpler to calculate than when set out in the usual way.

Roger Graham, near Gerringong, Australia

http://members.optusnet.com.au/~rogergraham